SQL/GROUP BY
GROUP BY, HAVING
jjhim531
2024. 8. 19. 19:53
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Q. 각 직급별 총사원수, 보너스를 받는 사람수, 급여합, 평균급여, 최저급여, 최고급여 (정렬 = 직급 오름차순)
SELECT
job_code AS "직급",
COUNT(*) AS "사원수",
COUNT(bonus) AS "보너스 받는 사람",
SUM(salary) AS "급여합",
round(AVG(salary)) AS "급여평균",
MIN(salary) AS "최저급여",
MAX(salary) AS "최고급여"
FROM
employee
GROUP BY
job_code
ORDER BY
job_code;
Q. 부서별 보너스를 받는 사원이 없는 부서의 부서코드
SELECT
dept_code,
COUNT(bonus)
FROM
employee
GROUP BY
dept_code
HAVING
COUNT(bonus) = 0;
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